LaMgAl11O19: Mn2+和LaMgAl11O19:RE, Mn2+(RE=Eu2+, Gd3+)的发光特性

Luminescence Properties of LaMgAl11O19:Mn2+ and LaMgAl11O19: RE, Mn2+(RE=Eu2+, Gd3+) under UV/VUV Excitation

摘要:

以H3BO3作助熔剂，用高温固相法在1150 ℃、保温4 h的条件下成功制备了LaMgAl11O19:Mn的单相粉末样品并研究了其真空紫外光激发下的一系列发光特性。在紫外光(254 nm)激发下，LaMgAl11O19: Mn不发光；真空紫外光(147 nm)激发下，观察到Mn2+很强的3d5→3d44s的跃迁发光，峰值位于516 nm，结果表明，Mn2+的掺杂浓度在0.05 mol/mol时发光最强。为了继续增强LaMgAl11O19中Mn2+的发光强度，在固定Mn2+的浓度为0.05 mol/mol的

Abstract:

Using H3BO3 as a flux, LaMgAl11O19:Mn2+ and LaMgAl11O19:RE, Mn2+(RE=Eu2+, Gd3+) were synthesized by solid state reaction at 1150 ℃ for 4 h. The effect of Mn2+ on the luminescent properties excited by vacuum ultraviolet (VUV) was investigated. The strong emission spectrum excited by 147 nm is composed of peaks from Eu2+ and Mn2+ luminescence in LaMgAl11O19:(Eu2+, Mn2+ ) and only Mn2+ luminescence in LaMgAl11O19:Mn2+ and LaMgAl11O19:(Gd3+, Mn2+). The results show that the green emission of Mn2+ becomes stronger because of efficient energy transferring from Eu2+ and Gd3+ to Mn2+